NOTE: Remember to convert Celcius to Kelvin when necessary 
2.1: Heat Capacity of Air
a) n=RT/poV
   W = Heat = (5/2)*n*R*(T2 - T1)
b) Heat = answer from part a  (Work/Heat does not depend on molecular weight)
c) CV = (5/2)*n*R  (use the n found in part a)


2.2: Isothermal Work on a Gas (constant temperature)
 NOTE: 1L = 10-3 m3    1atm = 1.013x105 Pa

a) pi=nRT/Vi  ... this answer is in Pa, convert to atm
   pf=nRT/Vf  ... this answer is in Pa, convert to atm
b) W = nRT*ln(V2/V1)
c) delta.U = Q - W  ::   delta.U = 0
   Q = W


2.3: Adiabatic Work on a Gas (no heat input)
a) pi=nRT/Vi  ... this answer is in Pa, convert to atm
   piViy = pfVfy  ::  y=7/5  ::  pi already in atm
b) pfVf = nRTf  ::  convert pf to from atm to Pa
c) W=(5/2)*n*R*(Tf-Ti)


2.4: Heat Cycle
a) p1V1=nRt=p2V2  ::  p2 = (p1*V1)/V2
   p3V3y = p1V1y  ::  p3 = (p1*V1y)/V3y
b) W1-2 = Q1-2 = nRT*ln(V2/V1)  ::  p1V1 = p2V2 = nRT
   W1-2 = Q1-2 = p1V1*ln(V2/V1)
c) W2-3 = 0
   Q2-3 = (3/2)*V*(p3-p2)  ::  your answer will be NEGATIVE
d) W3-1 = -delta.U3-1 = (3/2)(p3*V3-p1*V1)